GeeksForGeeks - Company Questions - Check if a number is Perfect Square.py

Check if a number is Perfect Square

 


Problem Statement:

Given a natural number n, print 1 if it is perfect square else 0.

Input:
The first line of input contains an integer T denoting the number of test cases. The first line of each test case is N, N is the number to be checked whether perfect square or not.

Output:
1 if it is perfect square else 0 

Constraints:
1 <= T <= 30
1 <= N <= 100000

Example:
Input:
3
100
10
125

Output:
1
0
0

Solution:

Language: Python

import math

n = input()

while(n>0):

    n-=1

    k = input()

    temp = int(math.sqrt(k))

    if (temp*temp == k):

        print 1

    else:

        print 0

Thanks for Visiting, Hope this helps you.... Comments are welcome....